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做OJ吧,首先要编译通过。。。In Reply To:帮忙。。谢谢 Posted by:00330001 at 2005-09-23 14:25:02 > 设计一个链表,先把N 个 2x+1顺序存进去,再按大小插入3x+1,并把后面的节点释放。
> 打印最后一个节点的值。。。
> 为什么???
> #include <stdlib.h>
> #include <stdio.h>
> typedef struct node* link;
> struct node{
> int item;
> link next;
> };
> main()
> {
> int i,n,x=0;
> int key=1;
> scanf("%d ", &n);
> link t=malloc(sizeof (node));
> link a;
> link last;
> t=a;
> for(i=1;i<=n;i++)
> {
> list a->next=malloc(sizeof (node));
> a=a->next;
> a->item=2*x+1;
> x++;
> }
> a=t;
> for(i=1;i<=n;i++)
> {
> t->item=3*key+1;
> a=a->next;
> if(a->item<t->item)
> {
> t=a->next;
> a->next=t->next;
> last=t;
> while(last->next->next)
> last->next=last->next->next;
> free(last->next->next);
> }
> }
> while(a->next)
> a=a->next;
> printf("%d\n", a->item);
>
> }
>
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