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bubblesort-_-In Reply To:已经用数字存储排序了,还是超时,谁给我看看 Posted by:donge at 2005-09-22 13:17:27 > #include <stdio.h>
>
> #include <string.h>
>
> int pw(int k){
> int pow=1;
> for(int i=0;i<6-k;i++)
> pow*=10;
> return pow;
> }
> int lib[100000];
> int lnum[100000];
> int x=0;
> void bubblesort()
> {
> int ii,jj,temp,tag;
>
> for(ii=0,tag=1;tag==1&&ii<x-1;ii++){
> tag=0;
> for(jj=0;jj<x-ii-1;jj++)
> if(lib[jj]>lib[jj+1]){
> temp=lib[jj];lib[jj]=lib[jj+1];lib[jj+1]=temp;
> temp=lnum[jj];lnum[jj]=lnum[jj+1];lnum[jj+1]=temp;
> tag=1;
> }
> }
> }
>
> int main()
> {
> int n;
> int i,j,k,len;
> char s[18];
> char t[18];
> int num=0;
>
> int dp=0;
>
> int ok=0;
>
> scanf("%d",&n);
>
> for(i=0;i<n;i++)
> {
> lnum[i]=0;
> lib[i]=-1;
> }
>
> for(i=0;i<n;i++)
> {
> num=0;
> scanf("%s",&s);
> len=strlen(s);
>
> for(j=0,k=0;j<len;j++)
> {
> switch(s[j])
> {
> case '0' ... '9' :
> num+=(s[j]-'0')*pw(k);
> k++;
> break;
> case '-':continue;
> case 'A' ... 'C':
> num+=2*pw(k);
> k++;
> break;
> case 'D' ... 'F':
> num+=3*pw(k);
> k++;
> break;
> case 'G' ... 'I':
> num+=4*pw(k);
> k++;
> break;
> case 'J' ... 'L':
> num+=5*pw(k);
> k++;
> break;
> case 'M' ... 'O':
> num+=6*pw(k);
> k++;
> break;
> case 'P' ... 'S':
> num+=7*pw(k);
> k++;
> break;
> case 'T' ... 'V':
> num+=8*pw(k);
> k++;
> break;
> case 'W' ... 'Y':
> num+=9*pw(k);
> k++;
> break;
> }
>
> }
>
> ok=0;
> for(j=0;j<x+1;j++)
> {
> if(lib[j]==num){
> ok=1;lnum[j]++;dp=1;break;
>
> }
> }
> if(ok==0){
> lib[x]=num;
> lnum[x]++;
> x++;
> }
> }
>
> bubblesort();
>
> if(dp==1)for(i=0;i<x;i++)
> {
> if(lnum[i]>1)
> printf("%03d-%04d %d\n",lib[i]/10000,lib[i]%10000,lnum[i]);
> }
> else printf("No duplicates.\n");
> return 0;
> }
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