Online Judge | Problem Set | Authors | Online Contests | User | ||||||
---|---|---|---|---|---|---|---|---|---|---|
Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest |
已经用数字存储排序了,还是超时,谁给我看看#include <stdio.h> #include <string.h> int pw(int k){ int pow=1; for(int i=0;i<6-k;i++) pow*=10; return pow; } int lib[100000]; int lnum[100000]; int x=0; void bubblesort() { int ii,jj,temp,tag; for(ii=0,tag=1;tag==1&&ii<x-1;ii++){ tag=0; for(jj=0;jj<x-ii-1;jj++) if(lib[jj]>lib[jj+1]){ temp=lib[jj];lib[jj]=lib[jj+1];lib[jj+1]=temp; temp=lnum[jj];lnum[jj]=lnum[jj+1];lnum[jj+1]=temp; tag=1; } } } int main() { int n; int i,j,k,len; char s[18]; char t[18]; int num=0; int dp=0; int ok=0; scanf("%d",&n); for(i=0;i<n;i++) { lnum[i]=0; lib[i]=-1; } for(i=0;i<n;i++) { num=0; scanf("%s",&s); len=strlen(s); for(j=0,k=0;j<len;j++) { switch(s[j]) { case '0' ... '9' : num+=(s[j]-'0')*pw(k); k++; break; case '-':continue; case 'A' ... 'C': num+=2*pw(k); k++; break; case 'D' ... 'F': num+=3*pw(k); k++; break; case 'G' ... 'I': num+=4*pw(k); k++; break; case 'J' ... 'L': num+=5*pw(k); k++; break; case 'M' ... 'O': num+=6*pw(k); k++; break; case 'P' ... 'S': num+=7*pw(k); k++; break; case 'T' ... 'V': num+=8*pw(k); k++; break; case 'W' ... 'Y': num+=9*pw(k); k++; break; } } ok=0; for(j=0;j<x+1;j++) { if(lib[j]==num){ ok=1;lnum[j]++;dp=1;break; } } if(ok==0){ lib[x]=num; lnum[x]++; x++; } } bubblesort(); if(dp==1)for(i=0;i<x;i++) { if(lnum[i]>1) printf("%03d-%04d %d\n",lib[i]/10000,lib[i]%10000,lnum[i]); } else printf("No duplicates.\n"); return 0; } Followed by:
Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator