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已经用数字存储排序了,还是超时,谁给我看看#include <stdio.h>
#include <string.h>
int pw(int k){
int pow=1;
for(int i=0;i<6-k;i++)
pow*=10;
return pow;
}
int lib[100000];
int lnum[100000];
int x=0;
void bubblesort()
{
int ii,jj,temp,tag;
for(ii=0,tag=1;tag==1&&ii<x-1;ii++){
tag=0;
for(jj=0;jj<x-ii-1;jj++)
if(lib[jj]>lib[jj+1]){
temp=lib[jj];lib[jj]=lib[jj+1];lib[jj+1]=temp;
temp=lnum[jj];lnum[jj]=lnum[jj+1];lnum[jj+1]=temp;
tag=1;
}
}
}
int main()
{
int n;
int i,j,k,len;
char s[18];
char t[18];
int num=0;
int dp=0;
int ok=0;
scanf("%d",&n);
for(i=0;i<n;i++)
{
lnum[i]=0;
lib[i]=-1;
}
for(i=0;i<n;i++)
{
num=0;
scanf("%s",&s);
len=strlen(s);
for(j=0,k=0;j<len;j++)
{
switch(s[j])
{
case '0' ... '9' :
num+=(s[j]-'0')*pw(k);
k++;
break;
case '-':continue;
case 'A' ... 'C':
num+=2*pw(k);
k++;
break;
case 'D' ... 'F':
num+=3*pw(k);
k++;
break;
case 'G' ... 'I':
num+=4*pw(k);
k++;
break;
case 'J' ... 'L':
num+=5*pw(k);
k++;
break;
case 'M' ... 'O':
num+=6*pw(k);
k++;
break;
case 'P' ... 'S':
num+=7*pw(k);
k++;
break;
case 'T' ... 'V':
num+=8*pw(k);
k++;
break;
case 'W' ... 'Y':
num+=9*pw(k);
k++;
break;
}
}
ok=0;
for(j=0;j<x+1;j++)
{
if(lib[j]==num){
ok=1;lnum[j]++;dp=1;break;
}
}
if(ok==0){
lib[x]=num;
lnum[x]++;
x++;
}
}
bubblesort();
if(dp==1)for(i=0;i<x;i++)
{
if(lnum[i]>1)
printf("%03d-%04d %d\n",lib[i]/10000,lib[i]%10000,lnum[i]);
}
else printf("No duplicates.\n");
return 0;
}
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