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我用了线段树啊In Reply To:为什么一次快排加一次插入还是超时啊? Posted by:zerocool_08 at 2005-09-14 12:32:34 Source
Problem Id:2489 User Id:zerocool_08
Memory:11800K Time:10015MS
Language:C++ Result:Time Limit Exceed
Source
#include "stdio.h"
#include "stdlib.h"
#include "memory.h"
int sum=0,flag,b[3000000]={0};
struct seg{
int x1;
int y1;
int x2;
int y2;
float x;
float point;
};
seg a[100001];
int compare(const void *arg1,const void *arg2)
{
if((*(seg *)arg1).x==(*(seg *)arg2).x)
return (int )((*(seg *)arg1).point-(*(seg *)arg2).point);
else
return (int)((*(seg *)arg1).x-(*(seg *)arg2).x);
}
void insert(int x)
{
int k=1,l=0,r=1000000,mid;
while(l<r)
{
mid = (l + r)/2;
if(x>mid)
l=mid+1,k=2*k+1;
else
b[k]++,r=mid,k*=2;
}
b[k]++;
}
int fd(int x)
{
int k=1,l=0,r=1000000,mid,s=0;
while(l<r)
{
mid =(l+r)/2;
if(x>mid)
l=mid+1,s+=b[k],k=2*k+1;
else
r=mid,k*=2;
}
return s;
}
void main(void)
{
int t,n,i,j,temp,k,m;
scanf("%d",&t);
for(i=1;i<=t;i++)
{
scanf("%d",&n);
for(j=0;j<n;j++)
{
scanf("%d%d%d%d",&a[j].x1,&a[j].y1,&a[j].x2,&a[j].y2);
if(a[j].x1==a[j].x2)
{
a[j].x=1000001;
a[j].point=(float)a[j].x1;
if(a[j].y1>a[j].y2)
{
temp=a[j].y1,a[j].y1=a[j].y2,a[j].y2=temp;
}
}
else
{
a[j].x=(float)(a[j].y2-a[j].y1)/(a[j].x2-a[j].x1);
a[j].point=a[j].y1-a[j].x*a[j].x1;
if(a[j].x1>a[j].x2)
{
temp=a[j].x1,a[j].x1=a[j].x2,a[j].x2=temp;
}
}
}
qsort(a,n,sizeof(seg),compare);
for(j=0,sum=0;j<n;)
{
if(a[j].x<1000001)
{
k=j+1;
memset(b,0,sizeof(b));
insert(a[j].x1);
while(a[k].x==a[j].x&&a[k].point==a[j].point&&k<n)
insert(a[k].x1),k++;
if(k-j>1)
{
for(m=j;m<k;m++)
sum+=fd(a[m].x2);
sum-=(k-j+1)*(k-j)/2;
}
j=k;
}
else
{
k=j+1;
memset(b,0,sizeof(b));
insert(a[j].y1);
while(a[k].x==a[j].x&&a[k].point==a[j].point&&k<n)
insert(a[k].y1),k++;
if(k-j>1)
{
for(m=j;m<k;m++)
sum+=fd(a[m].y2);
sum-=(k-j+1)*(k-j)/2;
}
j=k;
}
}
printf("Scenario #%d:\n%d\n\n",i,sum);
}
}
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