Online Judge | Problem Set | Authors | Online Contests | User | ||||||
---|---|---|---|---|---|---|---|---|---|---|
Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest |
我用了线段树啊In Reply To:为什么一次快排加一次插入还是超时啊? Posted by:zerocool_08 at 2005-09-14 12:32:34 Source Problem Id:2489 User Id:zerocool_08 Memory:11800K Time:10015MS Language:C++ Result:Time Limit Exceed Source #include "stdio.h" #include "stdlib.h" #include "memory.h" int sum=0,flag,b[3000000]={0}; struct seg{ int x1; int y1; int x2; int y2; float x; float point; }; seg a[100001]; int compare(const void *arg1,const void *arg2) { if((*(seg *)arg1).x==(*(seg *)arg2).x) return (int )((*(seg *)arg1).point-(*(seg *)arg2).point); else return (int)((*(seg *)arg1).x-(*(seg *)arg2).x); } void insert(int x) { int k=1,l=0,r=1000000,mid; while(l<r) { mid = (l + r)/2; if(x>mid) l=mid+1,k=2*k+1; else b[k]++,r=mid,k*=2; } b[k]++; } int fd(int x) { int k=1,l=0,r=1000000,mid,s=0; while(l<r) { mid =(l+r)/2; if(x>mid) l=mid+1,s+=b[k],k=2*k+1; else r=mid,k*=2; } return s; } void main(void) { int t,n,i,j,temp,k,m; scanf("%d",&t); for(i=1;i<=t;i++) { scanf("%d",&n); for(j=0;j<n;j++) { scanf("%d%d%d%d",&a[j].x1,&a[j].y1,&a[j].x2,&a[j].y2); if(a[j].x1==a[j].x2) { a[j].x=1000001; a[j].point=(float)a[j].x1; if(a[j].y1>a[j].y2) { temp=a[j].y1,a[j].y1=a[j].y2,a[j].y2=temp; } } else { a[j].x=(float)(a[j].y2-a[j].y1)/(a[j].x2-a[j].x1); a[j].point=a[j].y1-a[j].x*a[j].x1; if(a[j].x1>a[j].x2) { temp=a[j].x1,a[j].x1=a[j].x2,a[j].x2=temp; } } } qsort(a,n,sizeof(seg),compare); for(j=0,sum=0;j<n;) { if(a[j].x<1000001) { k=j+1; memset(b,0,sizeof(b)); insert(a[j].x1); while(a[k].x==a[j].x&&a[k].point==a[j].point&&k<n) insert(a[k].x1),k++; if(k-j>1) { for(m=j;m<k;m++) sum+=fd(a[m].x2); sum-=(k-j+1)*(k-j)/2; } j=k; } else { k=j+1; memset(b,0,sizeof(b)); insert(a[j].y1); while(a[k].x==a[j].x&&a[k].point==a[j].point&&k<n) insert(a[k].y1),k++; if(k-j>1) { for(m=j;m<k;m++) sum+=fd(a[m].y2); sum-=(k-j+1)*(k-j)/2; } j=k; } } printf("Scenario #%d:\n%d\n\n",i,sum); } } Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator