(*(p+i)).tyea=da/260;
这样不对
(*(p+i)).tyea＝（da%260==0?da/260-1:da/260)）

(*(p+i)).tday = st % 13;

也不对
(*(p+i)).tday ＝((st%13)!=0?(st%13):13)

你要考虑 ／ 正好整除时候
％ 正好是0的时候














> #include <stdio.h>
> #include <string.h>
> struct d{
> 	int tday;
> 	char tmon[9];
> 	int tyea;
> }re[100];
> void main(){
> 	char ha[20][7]={" ","pop", "no", "zip", "zotz", "tzec", "xul", "yoxkin","mol", 
> 		"chen", "yax", "zac", "ceh", "mac", "kankin", "muan", "pax", "koyab", "cumhu", "uayet"};
> 	char tz[21][9]={" ","imix", "ik", "akbal", "kan", "chicchan", "cimi", "manik",
> 		"lamat", "muluk", "ok", "chuen", "eb", "ben", "ix", "mem", "cib", "caban", 
> 		"eznab", "canac", "ahau"};
> 	int i,j,ca;
> 	int da;
> 	int st;//what remain after da is divided by 260
> 	int hda,hye;
> 	char hmon[9];
> 	scanf("%d",&ca);
> 	for(i=0; i<ca; i++){
> 		scanf("%d. %s %d",&hda, &hmon, &hye);
> 		//now transform to normal one(totalday)
> 		for (j=1; j<19; j++){
> 			if(strcmp(hmon,ha[j])==0){
> 				break;
> 			}
> 		}
> 		da=365*hye+(j-1)*20+hda+1;
> 		//now transform to hzo one
> 		re[i].tyea=da/260;
> 		st = da%260;
> 		strcpy(re[i].tmon,tz[st%20]);
> 		re[i].tday = st % 13;
> 	}
> 	printf("%d\n",ca);
> 	for(i=0; i<ca; i++){
> 		printf("%d %s %d\n",re[i].tday,re[i].tmon,re[i].tyea);
> 	}
> }
> 
> //another
> 
> /*
> #include <stdio.h>
> #include <string.h>
> #include <malloc.h>
> struct d{
> 	int tday;
> 	char tmon[9];
> 	int tyea;
> };
> void main(){
> 	struct d *p;
> 	char ha[20][7]={" ","pop", "no", "zip", "zotz", "tzec", "xul", "yoxkin","mol", 
> 		"chen", "yax", "zac", "ceh", "mac", "kankin", "muan", "pax", "koyab", "cumhu", "uayet"};
> 	char tz[21][9]={" ","imix", "ik", "akbal", "kan", "chicchan", "cimi", "manik",
> 		"lamat", "muluk", "ok", "chuen", "eb", "ben", "ix", "mem", "cib", "caban", 
> 		"eznab", "canac", "ahau"};
> 	int i,j,ca;
> 	int da;
> 	int st;//what remain after da is divided by 260
> 	int hda,hye;
> 	char hmon[9];
> 	scanf("%d",&ca);
> 	p=(struct d*)malloc(sizeof(struct d)*ca);
> 	for(i=0; i<ca; i++){
> 		scanf("%d. %s %d",&hda, &hmon, &hye);
> 		
> 		for (j=1; j<19; j++){
> 			if(strcmp(hmon,ha[j])==0){
> 				break;
> 			}
> 		}
> 		da=365*hye+(j-1)*20+hda+1;
> 		
> 		(*(p+i)).tyea=da/260;
> 		st = da%260;
> 		strcpy((*(p+i)).tmon,tz[st%20]);
> 		(*(p+i)).tday = st % 13;
> 	}
> 	printf("%d\n",ca);
> 	for(i=0; i<ca; i++){
> 		printf("%d %s %d\n",(*(p+i)).tday,(*(p+i)).tmon,(*(p+i)).tyea);
> 	}
> }*/