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测试数据通过,我自己试的几个数据也通过,但是wa,希望有高手提出意见谢谢,工具,dev-c++#include <iostream>
#include <stdlib.h>
#include <string>
using namespace std;
void multi(string&,string&,string&);
void predeal(string&,int&,int&);
void aftdeal(string&,int&);
int main()
{
string answerlist;
string s1,s2,t;int n,k=0;
while(cin>>s1>>n)
{
predeal(s1,k,n);
s2=s1;
while(n>1)
{
t.erase(t.begin(),t.end());
multi(s1,s2,t);
if (n==2) aftdeal(t,k);
for(int x=0;x<t.size();x++)
{
if (s1.size()>=x+1)s1[x]=t[t.size()-x-1];
else s1+=t[t.size()-x-1];
}
s1.erase(s1.begin()+t.size(),s1.end());
n--;
}
answerlist+=s1;
answerlist+='&';
}
answerlist+='@';
n=0;
while(answerlist[n]!='@')
{
if(answerlist[n]=='&') cout<<endl;
else cout<<answerlist[n];
n++;
}
system("PAUSE");
return 0;
}
void multi(string &a,string &b,string &t)
{
int e,i,j;
char t1;
for(i=0;i<a.size();i++)
{
e=0;
for(j=0;j<b.size();j++)
{
if(t.size()<i+j+1)
{
t+=char(((int(a[a.size()-i-1]-'0'))*(int(b[b.size()-j-1]-'0'))+e)%10+int('0'));
e= ((int(a[a.size()-i-1]-'0'))*(int(b[b.size()-j-1]-'0'))+e)/10;
}
else
{
t1=t[i+j];
t[i+j]=char((((int(a[a.size()-i-1]-'0'))*(int(b[b.size()-j-1]-'0'))+int(t1-'0')+e)%10)+int('0')); //+=...
e= ((int(a[a.size()-i-1]-'0'))*(int(b[b.size()-j-1]-'0'))+int(t1-'0')+e)/10;
}
}
if(e!=0)
if(t.size()<i+j+1)t+=char(e+int('0'));
}
}
void predeal(string& s,int& k,int& n)
{
string::size_type i=s.find('.');
if (i==string::npos) return;
k=(s.size()-i-1)*n;//结果后面应该有k位小数
s.erase(i,1);
}
void aftdeal(string& t,int& k)
{
t.insert(k,".");
int i=t.size();
while(t[i-1]=='0') i--;
if (i<t.size()) t.erase(t.begin()+i,t.end());
i=-1;
while(t[i+1]=='0') i++;
if(t[i+1]=='.') i++;
if (i>=0) t.erase(t.begin(),t.begin()+i+1);
}
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