#include <iostream>
using namespace std;
int main() {
	int a[1001];
	int n;
	int i,j;
	int sum,r;
	while(cin>>n) {
		sum=0;
		i=2; sum+=i;
		while(sum<=n) {
			a[i]=i;
			++i;
			sum+=i;
		}
		sum=sum-i;
		--i;
		r=i;
		if(sum==n){
			cout<<a[2];
			for(i=3;i<=r;i++)
				cout<<' '<<a[i];
		}
		else {
			for(i=2;i<=r;i++)
				if(a[i]+n-sum>a[r]){
					a[++r]=a[i]+n-sum;
					j=i;
					break;
				}
			if(j==2) {
				cout<<a[3];
				for(i=4;i<=r;i++)
					cout<<' '<<a[i];
				cout<<endl;
			}
			else {
				cout<<a[2];
				for(i=3;i<j;i++)
					cout<<' '<<a[i];
				for(i=j+1;i<=r;i++)
					cout<<' '<<a[i];
				cout<<endl;
			}
		}
	}
	return 0;
}

• 不必这样吧............不好 (799) mixter 2005-09-03 09:17:26
• sum=sum-i; (2) huicpc11 2005-11-07 01:25:58
  • Try sum -= (r = --i) + 1; ;-) (6) gongml 2005-11-08 06:41:15
• Re:通过的代码,看吧,很简单 (838) hudedi 2006-01-01 02:05:41
  • Re:通过的代码,看吧,很简单 (41) kevin655 2006-04-02 13:32:16
    • Re:通过的代码,看吧,很简单 (34) wulv 2007-03-05 20:58:49
  • Re:通过的代码,看吧,很简单 (1) level 2006-07-22 18:34:52
• 切 (22) yama 2006-07-18 09:50:18
• 很短的代码,哪位大侠可以看下哪里错了?所有的测试数据都搞对了啊 (383) dong930 2007-07-18 21:15:11