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直接dp比较好,复杂度低,报告所用的方法比较新颖,但是复杂度实际上比较高In Reply To:ft...rp真的有问题了...照着解题报告写了一个还是wa....郁闷....牛人帮看看.. Posted by:wavemoon at 2005-08-29 10:30:44 > code如下:
>
> #include<iostream.h>
> #include<stdlib.h>
> typedef struct lll
> {
> long long x,y;
> }Line;
> Line a[1000];
> long long n;
> long long map[1000][1000];
> long long temp[100][100];
> long long tp[100][100];
> int cmp(const void*a,const void*b)
> {
> Line aa,bb;
> aa=*(Line*)a;
> bb=*(Line*)b;
> if(aa.y!=bb.y) {
> if(aa.y>bb.y) return 1;
> else return -1;
> }
> else {
> if(aa.x>bb.x) return 1;
> else if(aa.x==bb.x) return 0;
> else return -1;
> }
> }
>
>
> main()
> {
> long long i,j,edg,k,tl,ff,t,ii;
> while(cin>>n)
> {
> for(i=0;i<n;i++)
> {
> cin>>a[i].x>>a[i].y;
> if(a[i].x>a[i].y)
> a[i].x^=a[i].y^=a[i].x^=a[i].y;
> }
> qsort(a,n,sizeof(a[0]),cmp);
> edg=a[0].x;
> k=0;
> for(i=0;i<n;i++)
> if(a[i].x>=edg)
> {
> k++;
> edg=a[i].y;
> }
>
> for(i=0;i<n;i++)
> for(j=0;j<n;j++)
> {
> if(a[j].x>=a[i].y) temp[i][j]=map[i][j]=1;
> else temp[i][j]=map[i][j]=0;
> }
> for(ff=0;ff<k-2;ff++)//A^(k-1)
> {
> for(i=0;i<n;i++)
> for(j=0;j<n;j++)
> {
> t=0;
> for(ii=0;ii<n;ii++) t+=temp[i][ii]*map[ii][j];
> tp[i][j]=t;
> }
> for(i=0;i<n;i++)
> for(j=0;j<n;j++)
> temp[i][j]=tp[i][j];
> }
> tl=0;
> for(i=0;i<n;i++)
> for(j=0;j<n;j++)
> tl+=temp[i][j];
>
> if(k==1) tl=n;
> cout<<n-k<<" "<<tl<<endl;
> }
> }
>
>
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