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直接dp比较好,复杂度低,报告所用的方法比较新颖,但是复杂度实际上比较高In Reply To:ft...rp真的有问题了...照着解题报告写了一个还是wa....郁闷....牛人帮看看.. Posted by:wavemoon at 2005-08-29 10:30:44 > code如下: > > #include<iostream.h> > #include<stdlib.h> > typedef struct lll > { > long long x,y; > }Line; > Line a[1000]; > long long n; > long long map[1000][1000]; > long long temp[100][100]; > long long tp[100][100]; > int cmp(const void*a,const void*b) > { > Line aa,bb; > aa=*(Line*)a; > bb=*(Line*)b; > if(aa.y!=bb.y) { > if(aa.y>bb.y) return 1; > else return -1; > } > else { > if(aa.x>bb.x) return 1; > else if(aa.x==bb.x) return 0; > else return -1; > } > } > > > main() > { > long long i,j,edg,k,tl,ff,t,ii; > while(cin>>n) > { > for(i=0;i<n;i++) > { > cin>>a[i].x>>a[i].y; > if(a[i].x>a[i].y) > a[i].x^=a[i].y^=a[i].x^=a[i].y; > } > qsort(a,n,sizeof(a[0]),cmp); > edg=a[0].x; > k=0; > for(i=0;i<n;i++) > if(a[i].x>=edg) > { > k++; > edg=a[i].y; > } > > for(i=0;i<n;i++) > for(j=0;j<n;j++) > { > if(a[j].x>=a[i].y) temp[i][j]=map[i][j]=1; > else temp[i][j]=map[i][j]=0; > } > for(ff=0;ff<k-2;ff++)//A^(k-1) > { > for(i=0;i<n;i++) > for(j=0;j<n;j++) > { > t=0; > for(ii=0;ii<n;ii++) t+=temp[i][ii]*map[ii][j]; > tp[i][j]=t; > } > for(i=0;i<n;i++) > for(j=0;j<n;j++) > temp[i][j]=tp[i][j]; > } > tl=0; > for(i=0;i<n;i++) > for(j=0;j<n;j++) > tl+=temp[i][j]; > > if(k==1) tl=n; > cout<<n-k<<" "<<tl<<endl; > } > } > > > > > > > > Followed by:
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