Online Judge | Problem Set | Authors | Online Contests | User | ||||||
---|---|---|---|---|---|---|---|---|---|---|
Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest |
异形?In Reply To:我也是那个的变种,不知道是不是错了, Posted by:Essence_me at 2005-08-15 11:16:22 > DIJ结构不变,然后每次寻找在X集合中到Y集合中最长的边,再更新DIST(如果COST[V][W]>DIST[W] 那么更新DIST) > 谁可以教教我这样做对不对? > 程序如下: > #include <stdio.h> > #include <memory.h> > #include <string.h> > #define true 1 > #define false 0 > #define I -9999 > int cost[200][20]; > int dist[200]; > int v0,v1; > int Teams=0,Index[200]; > char Name[200][100]; > > int GetID(char *NowName) > { > int i,j,k,b; > i = -1;j = Teams; > while (i < j-1) > { > k = (i+j)/2; > b = strcmp(Name[Index[k]],NowName); > if (!b) > { > return Index[k]; > } > if (b>0) > { > j=k; > } > else > { > i=k; > } > } > for (i=Teams;i>j;i--) > { > Index[i]=Index[i-1]; > } > > Index[j]=Teams; > strcpy(Name[Teams],NowName); > > Teams++; > return Teams-1; > } > > void main() > { > int final[200], i,j, v, v1,w,max,min,d,n,m,num=0; > char name[200],start[100],end[100]; > int x,y,distance,load[100]; > > while(1) > { > > num++; > scanf("%d%d", &n,&m); > if(n==0&&m==0)break; > memset(load,0,sizeof(int)*n); > for(i = 0; i < m; i++) > { > scanf("%s",name); > x=GetID(name); > scanf("%s", name); > y=GetID(name); > scanf("%d", &distance); > cost[x][y]=distance; > cost[y][x]=distance; > } > scanf("%s %s",start,end); > d=GetID(end); > v0=GetID(start); > for(i=0;i<n;i++) > for(j=0;j<n;j++) > { > if(cost[i][j]==0)cost[i][j]=I; > > } > for (v = 0; v < n; v++) > { > final[v] = false; > dist[v] = cost[v0][v]; > } > > > final[v0] = true; > load[v0]=-I; > v=v0; > for(i=1;i<n;i++) > { > max = I; > > v1=v; > for (w=0;w<n;w++) > { > if (!final[w]&&dist[w]>max) > { > max=dist[w]; > v=w; > } > } > final[v]=true; > if(max<load[v1])load[v]=max; > else load[v]=load[v1]; > for (w=0;w<n;w++) > { > if(!final[w]&&(cost[v][w]>dist[w])) > { > dist[w]=cost[v][w]; > } > } > } > printf("Scenerio #%d\n",num); > printf("%d tons\n\n",load[d]); > } > } Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator