Sample Input

O S, GOMR YPFSU/
Sample Output

I AM FINE TODAY.
题目就是要求吧输入的字符串，按照键盘的位置，把输出每个字符再键盘上，左边的那个字符，遇到空格仍然打空格，我写的代码是把输入部分的每个字符转化后输出，但是输出空格的时候竟然打了换行，很是郁闷那！
下面是我的代码：
/*
WERTYU




char a[26]={'Q','W','E','R','T','Y','U','I','O','P','A','S','D','F','G','H','J','K','L',
            'Z','X','C','V','B','N','M'};
char b[10]={'1','2','3','4','5','6','7','8','9','0'};
A common typing error is to place the hands on the keyboard one row to the right of the correct position. So "Q" is typed as "W" and "J" is typed as "K" and so on. You are to decode a message typed in this manner. 


Input

Input consists of several lines of text. Each line may contain digits, spaces, upper case letters (except Q, A, Z), or punctuation shown above [except back-quote (`)]. Keys labelled with words [Tab, BackSp, Control, etc.] are not represented in the input. 


Output

You are to replace each digit, letter or punctuation symbol by the one immediately to its left on the QWERTY keyboard shown above. Spaces in the input should be echoed in the output. 

Sample Input

O S, GOMR YPFSU/
Sample Output
I AM FINE TODAY.


char a[26]={'Q','W','E','R','T','Y','U','I','O','P','A','S','D','F','G','H','J','K','L',
            'Z','X','C','V','B','N','M'};
char b[10]={'1','2','3','4','5','6','7','8','9','0'};
*/
#include <stdio.h>
#include <string.h>
char a[46]={'1','2','3','4','5','6','7','8','9','0','-','=',
            'Q','W','E','R','T','Y','U','I','O','P','[',']','\\',
			'A','S','D','F','G','H','J','K','L',';','\'',
            'Z','X','C','V','B','N','M',',','.','/'};
int main()
{
	char s[1000];
	char b[1000];
	int i,j,k;
	while(scanf("%s",s)==1)
	{
		int len=0;
		k=0;
		len=strlen(s);
		for(i=0;i<len;i++)
		{
			if(s[i]==' ')
				b[k++]=s[i];
			else
			{
				for(j=1;j<46;j++)
				{
					if(s[i]==a[j])
						b[k++]=a[j-1];
				}
			}
		}
		b[k]='\0';
		for(i=0;i<k;i++)
		    printf("%c",b[i]);
        printf("\n");   
	}
	return 0;
}