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假如你的无穷大相加没溢出的话就不该有问题了,标准的bfs+km/mcmf

Posted by cero at 2005-08-07 11:46:29
In Reply To:这种情况我把不可达的匹配边权值设为无穷大,应该没有问题吧! Posted by:zhucheng at 2005-08-07 11:43:36


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