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就像这个,标程的核心部分In Reply To:最经典的在DP中解决精度问题, double ok Posted by:sunmoonstar_love at 2005-08-05 22:20:44 for (i=1;i<n;i++) { for (j=0;j<k;j++) x[i][j] += x[i-1][j]/k; for (j=1;j<k;j++) x[i][j] += x[i-1][j-1]/k; for (j=0;j<k-1;j++) x[i][j] += x[i-1][j+1]/k; } Followed by: Post your reply here: |
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