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不要每次加1，找到23的倍数后每次加23，找到28的倍数后每次加23*28In Reply To:怎样才能令它不超时呢?救命啊 Posted by:90303109 at 2003-11-16 16:55:18 > #include<math.h>
> #include<stdio.h>
> void main(){
> int p,e,i,d,n,k,m,date,endp;
> n=1;
> do{ scanf("%d %d %d %d",&p,&e,&i,&d);
> endp=0,m=0,date=d+1;
> while(endp!=1&&p!=-1){
> if((date-p)%23==0&&(date-e)%28==0&&(date-i)%33==0){
> printf("Case %d: the next triple peak occurs in %d days.\n",n,date-d);
> endp=1;
> n=n+1;
> }
> date=date+1;
> }
> }while(p!=-1&&e!=-1&&i!=-1&&d!=-1);
> }
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