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scanf("%Id",&k); %Id 什么东西,我一般都用 %lld %I64dIn Reply To:那位高手帮我看一下我的程序为什么WA?谢了。 Posted by:zxqi_009 at 2005-08-01 10:21:38 > #include<iostream> > > using namespace std; > > __int64 p,r,k1,k2,n=0,s[20],q[15],k,kbefore; > > int s_i,q_i; > > > int sum(__int64 k,__int64 *s,int s_i,int sign) > { k1=0; > __int64 temp,temp1,begin1,begin,end,mid; > > while(k1<k) > { > temp=(s[s_i+1]-s[s_i])*s_i; > if(k1+temp<k) > {k1+=temp; s_i++;} > else break; > > } > if(k1+temp==k) > { > if(sign==0)temp1=(s[s_i+1]-1)*(s[s_i+1]-1); > else temp1=s[s_i+1]-1; > p=temp1%10; > k1=k; > } > else > { begin=s[s_i],end=s[s_i+1]-1,begin1=begin; > while(begin<=end) > { > mid=(begin+end)/2; > if((mid-begin1+1)*s_i+k1>k) > { > if((mid-begin1)*s_i+k1<k) > { if(sign==0)p=mid*mid; > else p=mid; > k1+=(mid-begin1+1)*s_i; > break; > } > else end=mid-1; > } > else if((mid-begin1+1)*s_i+k1<k) > { > if((mid-begin1+2)*s_i+k1>k) > { if(sign==0)p=(mid+1)*(mid+1); > else p=mid+1; > k1+=(mid-begin1+2)*s_i; > break; > } > else begin=mid+1; > } > else > { if(sign==0)p=mid*mid; > else p=mid; > k=k1; > break; > } > } > } > for(int i=0;i<k1-k;i++) > p/=10; > > return p%10; > } > > int sum1(__int64 k) > { > int Sum=sum(k,s,1,0)+sum(k,q,1,1); > return Sum; > } > > int Inc(__int64 k) > { > int m=1,t=1; > while(t) > { > int temp=sum1(k+m); > while(temp>9) > { > m++; > temp=sum1(k+m); > } > t=0; > if(temp==9&&sum1(k+m+1)>9) > m+=2; > > } > while(m>1) > { > t=(t+sum1(k+m-1))/10; > m--; > } > return t; > } > > int main() > { > s[1]=1,s[2]=4,s[3]=10,s[4]=32,s[5]=100,s[6]=317,s[7]=1000,s[8]=3163,s[9]=10000,s[10]=31623; > s[11]=100000,s[12]=316228,s[13]=1000000,s[14]=3162278,s[15]=10000000,s[16]=31622777,s[17]=100000000; > s[18]=316227767,s[19]=1000000000; > > q[1]=1,q[2]=10,q[3]=100,q[4]=1000,q[5]=10000,q[6]=100000,q[7]=1000000,q[8]=10000000,q[9]=100000000; > q[10]=1000000000,q[11]=10000000000,q[12]=100000000000,q[13]=1000000000000,q[14]=10000000000000; > > scanf("%Id",&k); > while(k) > { > cout<<(sum1(k)+Inc(k))%10; > cout<<endl; > scanf("%Id",&k); > } > return 0; > > return 0; > } > Followed by:
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