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Re:就是个BFS,还是TLE阿codeIn Reply To:时限是不是太紧了,这样都TLE,过得程序快的就那两个阿 Posted by:lookus at 2005-07-31 23:07:27 #include <iostream.h>
#include <string.h>
#include <algorithm>
#define inf 20000000
#define KB(i) (k&(1<<(i)))
#define BIN(i) (1<<(i))
int b[1<<16],v[1<<16],s[1<<16],min,sum;
int a[]={51,102,204,816,1632,3264,13056,26112,52224};
char str[20];
void minBFS(char c)
{
int k=0,r,f,i,j,d;
for(i=0;i<16;++i)
if(str[i]==c)
k |= BIN(i);
d = k;
std::fill(v,v+(1<<16),inf);
memset(b,0,sizeof(b));
for(i=0;i<9;++i)
v[a[i]]=0,s[i]=a[i],b[a[i]]=1;
for(r=0,f=9;v[d]==inf || v[s[r]]<r;++r)
{
k = s[r];
for(i=0;i<16;++i)
if(k&BIN(i))
{
if(i-4>=0 && !KB(i-4))
{
j = ((k|BIN(i-4))&(~BIN(i)));
if(v[j]==inf)
{
v[j] = v[k]+1;
s[f++] = j;
b[j]=b[k];
}
else
if(v[j]==v[k]+1)
b[j]+=b[k];
}
if(i+4<16 && !KB(i+4))
{
j = ((k|BIN(i+4))&(~BIN(i)));
if(v[j]==inf)
{
v[j] = v[k]+1;
s[f++] = j;
b[j]=b[k];
}
else
if(v[j]==v[k]+1)
b[j]+=b[k];
}
if(i%4 != 0 && !KB(i-1))
{
j = ((k|BIN(i-1))&(~BIN(i)));
if(v[j]==inf)
{
v[j] = v[k]+1;
s[f++] = j;
b[j]=b[k];
}
else
if(v[j]==v[k]+1)
b[j]+=b[k];
}
if(i%4!=3 && !KB(i+1))
{
j = ((k|BIN(i+1))&(~BIN(i)));
if(v[j]==inf)
{
v[j] = v[k]+1;
s[f++] = j;
b[j]=b[k];
}
else
if(v[j]==v[k]+1)
b[j]+=b[k];
}
}
}
if(min < v[d])
return ;
if(min == v[d])
sum += b[d];
else
{
min = v[d];
sum = b[d];
}
}
void minStep()
{
min = inf;
minBFS('A');
minBFS('B');
minBFS('C');
minBFS('D');
}
void main()
{
char st[4];
int i;
while(cin>>str)
{
for(i=0;i<3;++i)
{
cin>>st;
strcat(str,st);
}
minStep();
cout<<min<<" "<<sum<<endl;
}
}
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