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修改一下,减小常数吧,感觉你的常数不小In Reply To:时限是不是太紧了,这样都TLE,过得程序快的就那两个阿 Posted by:lookus at 2005-07-31 23:07:27 > #include <iostream.h>
> #include <string.h>
> #include <algorithm>
> #define inf 20000000
> #define KB(i) (k&(1<<(i)))
> #define BIN(i) (1<<(i))
> int b[1<<16],v[1<<16],s[1<<16],min,sum;
> int a[]={51,102,204,816,1632,3264,13056,26112,52224};
> char str[20];
> int maxDFS(int k,int step)
> {
> return 0;
> }
> int dfs(int k,int dep)
> {
> if(b[k]!=-1)
> return b[k];
> if(v[k]!=dep)
> return 0;
> int i,d=0;
> --dep;
> for(i=0;i<16;++i)
> if(k&BIN(i))
> {
> if(i-4>=0 && !KB(i-4))
> d += dfs((k|BIN(i-4))&(~BIN(i)),dep);
> if(i+4<16 && !KB(i+4))
> d += dfs((k|BIN(i+4))&(~BIN(i)),dep);
> if(i%4 != 0 && !KB(i-1))
> d += dfs((k|BIN(i-1))&(~BIN(i)),dep);
> if(i%4!=3 && !KB(i+1))
> d += dfs((k|BIN(i+1))&(~BIN(i)),dep);
> }
> return b[k] = d;
> }
> void minBFS(char c)
> {
> int k=0,r,f,i,j,d;
> for(i=0;i<16;++i)
> if(str[i]==c)
> k |= BIN(i);
> d = k;
> std::fill(v,v+(1<<16),inf);
> for(i=0;i<9;++i)
> v[a[i]]=0,s[i]=a[i];
> for(r=0,f=9;v[d]==inf;++r)
> {
> k = s[r];
> for(i=0;i<16;++i)
> if(k&BIN(i))
> {
> if(i-4>=0 && !KB(i-4))
> {
> j = ((k|BIN(i-4))&(~BIN(i)));
> if(v[j]==inf)
> {
> v[j] = v[k]+1;
> s[f++] = j;
> }
> }
> if(i+4<16 && !KB(i+4))
> {
> j = ((k|BIN(i+4))&(~BIN(i)));
> if(v[j]==inf)
> {
> v[j] = v[k]+1;
> s[f++] = j;
> }
> }
> if(i%4 != 0 && !KB(i-1))
> {
> j = ((k|BIN(i-1))&(~BIN(i)));
> if(v[j]==inf)
> {
> v[j] = v[k]+1;
> s[f++] = j;
> }
> }
> if(i%4!=3 && !KB(i+1))
> {
> j = ((k|BIN(i+1))&(~BIN(i)));
> if(v[j]==inf)
> {
> v[j] = v[k]+1;
> s[f++] = j;
> }
> }
> }
> }
> if(min < v[d])
> return ;
> std::fill(b,b+(1<<16),-1);
> for(i=0;i<9;++i)
> b[a[i]] = 1;
> k = dfs(d,v[d]);
> if(min == v[d])
> sum += k;
> else
> {
> min = v[d];
> sum = k;
> }
> }
>
> void minStep()
> {
> min = inf;
> minBFS('A');
> minBFS('B');
> minBFS('C');
> minBFS('D');
> }
> void main()
> {
> char st[4];
> int i;
> while(cin>>str)
> {
> for(i=0;i<3;++i)
> {
> cin>>st;
> strcat(str,st);
> }
> minStep();
> cout<<min<<" "<<sum<<endl;
> }
> }
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