#include<stdio.h>
int f(int n,int m)
{
	if(n<=0)return 0;
	return (n>=m?m:n)+f(n-2*m,m);
}
int main()
{
	int n,m;
	scanf("%d%d",&n,&m);
	printf("%d\n",f(n,m));
	return 0;
}

• 貌似真不是~~状态也太简单了，漏洞太多 (2) dut200901102 2011-05-05 15:08:31