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复杂度是n^2 的In Reply To:为什么TLE呢? WA的话还可以理解 Posted by:sunmoonstar_love at 2005-07-28 19:45:54 > #include <iostream> > #include <string> > using namespace std; > string book[2600]; > int i,j,n,favor[2600],f[2600],pre[2600],answer[2600],num,max1,tmp; > void shell_sort(string* a, int n) > { > int gap,i,j,tmp1; > string tmp; > for(gap = 1; (gap *= 3) < n; gap++) > ; > for(gap /= 3; gap > 0; gap = (gap+1)/3) > for(i = gap; i < n; i++) > for(j = i - gap; j >= 0; j -= gap) > { > if(a[j+gap]<a[j]) > { > tmp = a[j]; a[j] = a[j+gap]; a[j+gap]= tmp; > tmp1 = favor[j]; favor[j] = favor[j+gap]; favor[j+gap] = tmp1; > } > else > break; > } > } > bool check(string a, string b) { > int pa,pb,ac,bc; > pa = pb = 0; > while (pa < a.size() && pb < b.size()) { > while (!(a[pa]>='a'&&a[pa]<='z' || a[pa]>='A'&&a[pa]<='Z') && pa < a.size()) pa++; > while (!(b[pb]>='a'&&b[pb]<='z' || b[pb]>='A'&&b[pb]<='Z') && pb < b.size()) pb++; > if (pa == a.size() || pb == b.size()) break; > if (a[pa]>='a'&&a[pa]<='z') ac = a[pa]-'a'; > else ac = a[pa]-'A'; > if (b[pb]>='a'&&b[pb]<='z') bc = b[pb]-'a'; > else bc = b[pb]-'A'; > if (ac == bc) return false; > pa++; pb++; > } > return true; > } > int main() > { > while(cin>>n) > { > for(i=0; i<n; i++) > { > cin>>favor[i]; > cin.get(); > getline(cin,book[i]); > // cout<<book[i]<<endl; > // cin.get(); > } > shell_sort(book,n); > /* for(i=0; i<n; i++) > { > cout<<favor[i]<<" "<<book[i]<<endl; > } */ > pre[0] = -1; > f[0] = favor[0]; > for(i=1; i<n; i++) > { > f[i] = tmp = favor[i]; > pre[i] = -1; > for(j=0; j<i; j++) > { > if(check(book[j],book[i])) > { > if(f[i]+f[j]>tmp) > { > tmp = f[i]+f[j]; > pre[i] = j; > } > } > } > f[i] = tmp; > > } > max1 = 0; > for(i=1; i<n; i++) > { > if(f[i]>f[max1]) > max1 = i; > } > answer[0] = max1; > num = 1; > i = max1; > while(pre[i]!=-1) > { > i = pre[i]; > answer[num++] = i; > } > cout<<num<<endl<<f[max1]<<endl; > while(num--) > { > cout<<book[answer[num]]<<endl; > } > } > return 0; > } > Followed by:
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