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t是整型 t/12.0 和1.0*t/12 有区别么？

Posted by nestle at 2005-07-27 19:34:57 on Problem 2510

Followed by:

浮点数会有些误差，我觉得没有大区别 (0) sunmoonstar_love 2005-07-27 19:47:04
- 什么意思能说清楚点么？就是说答案会不同么？ (0) nestle 2005-07-27 19:53:10
  - no difference if t is int (0) frkstyc 2005-07-27 19:53:48
    - nor if it is floating point (0) frkstyc 2005-07-27 19:54:13
      - But I really got WA，and ACed after I change it。 (0) nestle 2005-07-27 20:40:10
如果t就是一个变量，那么没有区别，如果是一个a*b的东西，就有区别了哦 (0) Kora 2005-07-27 20:42:47
- enen (0) frkstyc 2005-07-27 20:43:00
  - temp=8.0*cho[j].n-1.0*(query[i]-cho[j].t)/12; 改成（query[i]-cho[j].t)/12.0 就WA (0) nestle 2005-07-27 21:03:09
    - 有人帮忙么？ (0) nestle 2005-07-27 21:44:24
      - 挂在误差上面，/12.0我估计99%被G++优化成了*0.083333333333333333333333，误差就此而来 (0) frkstyc 2005-07-27 21:45:44

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