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用ABsinC/2求面积 ---->In Reply To:主过程没有问题. Posted by:c0500448242 at 2005-07-21 20:57:01 double getarea(int a, int b, int c) { int t1, t2, t3; double s1, s2, s3; t1 = (c + n - a) % n; s1 = d * sin(t1 * alph) / 2; t2 = (b + n - a) % n; s2 = d * sin(t2 * alph) / 2; t3 = (c + n - b) % n; s3 = d * sin(t3 * alph) / 2; return s2 + s3 - s1; } 调用的时候修改为 getarea(0, cc[p], cc[i]); getarea(0, cc[p - 1], cc[i]); getarea(cc[i], cc[q], 0); getarea(cc[i], cc[q - 1], 0); Followed by:
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