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请教dynamic nnlogn的算法 你是"在O(nlogn)的时间求出一个序列的长度>=k的平均值最大的子串m"吗In Reply To:没那么简单吧?nlogn的方法都已经有点复杂了... Posted by:dynamic at 2003-11-03 21:02:18 Followed by: Post your reply here: |
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