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你ac的是989ms,时间上稍微误差一点就超时In Reply To:同样的程序 不一样的结果?WHY? Posted by:heiheigo at 2005-07-10 11:26:35 > Source > > Problem Id:1006 User Id:heiheigo > Memory:28K Time:989MS > Language:C Result:Accepted > > Source > > #include "stdio.h" > int main(){ > int p,e,i,d; > int j=1; > int k=1; > long r; > while(scanf("%d%d%d%d",&p,&e,&i,&d)){ > if(p==-1) > break; > while(k){ > //r=p+(k-1)*23; > > if((k-p)%23==0&&(k-e)%28==0&&(k-i)%33==0){ > k=k-d; > if(k<=0) > k+=21252; > break; > } > k++; > } > printf("Case %d: the next triple peak occurs in %ld days.\n", j, k); > j++; > k=1; > } > return 0; > } > > > > Source > > Problem Id:1006 User Id:heiheigo > Memory:28K Time:1004MS > Language:C Result:Time Limit Exceed > > Source > > #include "stdio.h" > int main(){ > int p,e,i,d; > int j=1; > int k=1; > long r; > while(scanf("%d%d%d%d",&p,&e,&i,&d)){ > if(p==-1) > break; > while(k){ > //r=p+(k-1)*23; > > if((k-p)%23==0&&(k-e)%28==0&&(k-i)%33==0){ > k=k-d; > if(k<=0) > k+=21252; > break; > } > k++; > } > printf("Case %d: the next triple peak occurs in %ld days.\n", j, k); > j++; > k=1; > } > return 0; > } > > > Followed by: Post your reply here: |
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