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Re:这样有点慢，这题直接有公式，[n/2]*[(n-1)/2]In Reply To:这样有点慢，这题直接有公式，[n/2]*[(n-1)/2] Posted by:dynamic at 2003-11-01 21:35:48 o(n) 第一个逆序数显然是 n*(n-1)/2 然后就是没移动一个数， 求出逆序数的变化量 不过没有公式爽 ：P Followed by:
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