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我写了一个,供参考。In Reply To:很麻烦 Posted by:xfxyjwf at 2005-07-05 11:04:16 begin accu:0 pc:0 01 run:00111110 accu:11111111 pc:1 02 run:10100000 accu+1:00000000 pc:2 03 run:01010000 accu:00000000 pc:16 04 run:00111111 accu:10001001 pc:17 05 run:10000000 accu:10001000 pc:18 06 run 00000010 accu:10001000 memory byte 2 change into 10001000 pc:19 07 run 11000010 accu:10001000 pc:2 08 run 10001000 accu:10000111 pc:3 09 run 11100000 accu:10000111 promgram ends result: output 10000111 Followed by: Post your reply here: |
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