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Re:请高手帮忙. 我怎么也找不到 wa的数据.In Reply To:请高手帮忙. 我怎么也找不到 wa的数据. Posted by:slwgu at 2005-06-29 01:58:29 经典! 思路和我当时wa的相当类似,但显然还不如我的那个更加逼近正确解:) 还是老老实实的匹配吧,这题数据很好的说^_^ > 我真的找不到 wa的情况. > 请告诉我一些数据. > #include <iostream.h> > > int a[34][34]; > int b[34][34]; > int ch; > int s; > int m,n,k; > > void check(int sx,int sy, int ss) > { > if (ss==s) ch=1; > if (ch==1) return; > if (sx==m && sy==(n+1)) return; > if (sy==(n+1)) {sx++;sy=1;} > > int tx,ty; > int tmp; > > if (b[sx][sy]!=0) > check(sx,sy+1,ss); > > if (b[sx][sy]==0) > { > b[sx][sy]=1; > tx=sx;ty=sy+1; > if (b[tx][ty]==0) > { > if ((--a[sx+1][sy])==0) {a[sx+1][sy]++;goto nxt;} > if ((--a[tx+1][ty])==0) {a[tx+1][ty]++;goto nxt;} > if ((--a[tx][ty+1])==0) {a[tx][ty+1]++;goto nxt;} > b[tx][ty]=1; > check(sx,sy+1,ss+2); > b[tx][ty]=0; > if (ch==1) return; > a[sx+1][sy]++; > a[tx+1][ty]++; > a[tx][ty+1]++; > } > nxt: > tx=sx+1;ty=sy; > if (b[tx][ty]==0) > { > if ((--a[sx][sy+1])==0) {a[sx][sy+1]++;goto nxt1;} > if ((--a[tx+1][ty])==0) {a[tx+1][ty]++;goto nxt1;} > if ((--a[tx][ty+1])==0) {a[tx][ty+1]++;goto nxt1;} > if ((--a[tx][ty-1])==0) {a[tx][ty-1]++;goto nxt1;} > b[tx][ty]=1; > check(sx,sy+1,ss+2); > b[tx][ty]=0; > if (ch==1) return; > a[sx][sy+1]++; > a[tx+1][ty]++; > a[tx][ty+1]++; > a[tx][ty-1]++; > } > nxt1: > b[sx][sy]=0; > } > } > > int main() > { > int i,j; > int x,y; > cin>>m>>n>>k; > for (i=0;i<=m+1;i++) > for (j=0;j<=n+1;j++) > { > if ((i>0) && (i<=m) && (j>0) && (j<=n)) > a[i][j]=b[i][j]=0; > else > a[i][j]=b[i][j]=-1; > } > for (i=0;i<k;i++) > { > cin>>x>>y; > a[y][x]=b[y][x]=-1; > } > s=m*n-k; > if (s%2==1) > { > cout<<"NO"<<endl; > return 0; > } > > ch=1; > for (i=1;i<=m;i++) > for (j=1;j<=n;j++) > { > if (a[i][j]==0) > { > if (a[i-1][j]!=-1) a[i][j]++; > if (a[i+1][j]!=-1) a[i][j]++; > if (a[i][j-1]!=-1) a[i][j]++; > if (a[i][j+1]!=-1) a[i][j]++; > if (a[i][j]==0) {ch=0; goto ext;} > } > } > ext: > if (ch==0) > { > ch=0; > check(1,1,0); > } > if (ch==1) cout<<"YES"<<endl; else cout<<"NO"<<endl; > return 0; > } > > > > > > > > > > > > Followed by: Post your reply here: |
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