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我的思路没问题吧？In Reply To:ft....哪有这样的，比赛的时候谁给你测试数据啊，自己仔细调吧 Posted by:frkstyc at 2005-06-30 18:49:26 我的思路是把第i个人听见第j棵树倒记做pt[i-1][j-1]=1;然后比较pt[0]~pt[P-1]，r=P;有一组相同的就r--； Followed by:
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