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难得我写了个线段树呢

Posted by uni at 2005-06-26 18:12:27 on Problem 2452
In Reply To:我的方法是严格ONLOGN德,居然也那么慢....数据太弱了吧... Posted by:uni at 2005-06-26 18:10:26

Followed by:

我rmq... (0) ArXoR 2005-06-26 18:49:16
- 我的XXX超了 (0) frkstyc 2005-06-26 18:55:11
  - XXX? (0) ArXoR 2005-06-26 18:57:25
    - brute force...不要逼我写出来嘛 (0) frkstyc 2005-06-26 18:58:35
      - ...you said it,I didn't...^_^ (0) ArXoR 2005-06-26 18:59:35
        Copyright. All Rights Also Reserved. (0) frkstyc 2005-06-26 19:00:02
        @_@ (0) ArXoR 2005-06-26 19:02:41
有没线性算法呢? (0) ArXoR 2005-06-26 19:02:59
- 用RMQ+D&C就应该是O(n)的吧 (0) frkstyc 2005-06-26 19:03:43
  - 呃...好像对哦,汗...我没分治,迭代了一下 (0) ArXoR 2005-06-26 19:07:05
  - 光RMQ就有nlogn了，怎么可能到O(n)呢？看来我的RMQ+D&C7xxms的成绩已经没有优化余地了~~~~~ (0) palmtenor 2005-07-29 22:03:30
    - re (0) palmtenor 2005-07-29 22:20:07
      - b4 (0) frkstyc 2005-07-29 22:29:46
        遭bs的不是你么...... (0) palmtenor 2005-07-29 22:30:56
        显然是palmtenor，利用LCA搞就可以做到O(n)，你还是去多吃点饭吧 (0) frkstyc 2005-07-29 22:34:42
        我知道可以用RMQ做到o(n)的LCA....能反过来么？ (0) palmtenor 2005-07-29 22:42:40
        所以说你要吃饭 (0) frkstyc 2005-07-29 22:43:54
        您告诉我吧.....拜.....我只知道+-1的RMQ能做到O(n).... (0) palmtenor 2005-07-29 22:51:35
        bg我和TN吧 (0) frkstyc 2005-07-29 22:51:52
        西门鸡翅...... (0) palmtenor 2005-07-29 22:58:49
        也成 (0) frkstyc 2005-07-29 23:00:04
        greedy````` (0) palmtenor 2005-07-29 23:00:55
        一般RMQ问题可以用迪卡尔树转化为+-1RMQ问题 (0) Spacesheep 2005-08-24 13:05:11
        那天赫然发现srbga上就有讲....会了````` (0) palmtenor 2005-08-24 13:48:57
- Re:有没线性算法呢? (15) Lucifer 2005-09-05 16:05:11

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