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Re:我的测试数据都是对的,实在找不到错误,大神们帮我找找,感激不尽In Reply To:太伟大了 Posted by:BYR2012 at 2013-04-16 18:58:30 #include <iostream> #include <map> #include <string> using namespace std; int main(void) { map<string, int> hmonth; //maps a haab month to a number map<int, string> tmonth; //maps a number to a Tzo month hmonth["pop"] = 0; hmonth["no"] = 1; hmonth["zip"] = 2; hmonth["zotz"] = 3; hmonth["tzec"] = 4; hmonth["xul"] = 5; hmonth["yoxkin"] = 6; hmonth["mol"] = 7; hmonth["chen"] = 8; hmonth["yax"] = 9; hmonth["zac"] = 10; hmonth["ceh"] = 11; hmonth["mac"] = 12; hmonth["kankin"] = 13; hmonth["muan"] = 14; hmonth["pax"] = 15; hmonth["koyab"] = 16; hmonth["cumbu"] = 17; hmonth["uayet"] = 18; tmonth[1] = "imix"; tmonth[2] = "ik"; tmonth[3] = "akbal"; tmonth[4] = "kan"; tmonth[5] = "chicchan"; tmonth[6] = "cimi"; tmonth[7] = "manik"; tmonth[8] = "lamat"; tmonth[9] = "muluk"; tmonth[10] = "ok"; tmonth[11] = "chuen"; tmonth[12] = "eb"; tmonth[13] = "ben"; tmonth[14] = "ix"; tmonth[15] = "mem"; tmonth[16] = "cib"; tmonth[17] = "caban"; tmonth[18] = "eznab"; tmonth[19] = "canac"; tmonth[20] = "ahau"; int n; //number of dates to be transformed cin >> n; int *day = new int[n]; string *month= new string[n]; int *year = new int[n]; for(int i = 0; i < n; i++) { cin >> day[i]; cin.get(); cin >> month[i]; cin >> year[i]; } cout << n << endl; for(int i = 0; i < n; i++) { int numday = 0; numday += 365 * year[i]; numday += 20 * hmonth[month[i]]; numday += day[i] + 1; int tnum = 0; string tmpm = ""; int tyear = 0; if(numday % 260 == 0) tyear = numday / 260 - 1; else tyear = numday / 260; //numday %= 260; if(numday % 20 == 0) tmpm = tmonth[20]; else tmpm = tmonth[numday % 20]; if(numday % 13 == 0) tnum = 13; else tnum = numday % 13; cout << tnum << " " << tmpm << " " << tyear << endl; } return 0; } Followed by: Post your reply here: |
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