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Re:我有个证明，大家可以讨论一下。。In Reply To:我有个证明，大家可以讨论一下。。 Posted by:cug_fish2008 at 2010-05-10 10:54:59 蒽，这个应该不难想到。关键是怎样快速给出N,M条件的所有 gcd(x1,x2,..xn,M)=1 的方法数呢 Followed by:
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