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Re:快速幂取模学下再做,模板供参考In Reply To:快速幂取模学下再做,模板供参考 Posted by:ZJNU09220229 at 2010-11-24 22:00:31 > #include <cstdlib> > #include <stdio.h> > using namespace std; > long f(long a,long k,long M){//求a^k%M > long b=1; > while(k>=1){ > if(k%2==1){ > b=a*b%M; > } > a=(a%M)*(a%M)%M; > k/=2; > } > return b; > } > int main(int argc, char** argv) { > int t,n,i,j; > long a,b,M; > long z,ans; > scanf("%d",&t); > while(t--) > { > scanf("%ld",&M); > scanf("%d",&n); > ans=0; > for(i=0;i<n;i++) > { > scanf("%ld%ld",&a,&b); > z=f(a,b,M); > ans=(ans+z)%M; > } > printf("%ld\n",ans); > } > return 0; > } Followed by: Post your reply here: |
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