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感觉好简单啊,是不是很多人想复杂了。。。。一次AC,0ms。。#include <stdio.h>
char s[100001];
char t[100001];
int main(void){
int i,j;
while(scanf("%s %s",s,t)!=EOF){
i=0;
j=0;
while(s[i]&&t[j]){
if(s[i]==t[j]){
i++;
j++;
}else{
j++;
}
}
if(!s[i]){
printf("Yes\n");
}else{
printf("No\n");
}
}
return 0;
}
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