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水过，提供思路。。。。。。

Posted by 058179 at 2013-03-17 17:11:31 on Problem 1221 and last updated at 2013-09-30 17:34:48 
d[i,j] = ∑d[i - 2*j][k]; k= j....i-2*j; (i>= 2*j)
d[i,j] = 0 (i<2*j);
d[i,j] = 1 (i ==j);
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