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c++#include <cstdio>
#include <cstring>
#include <iostream>
#include <string>
using namespace std;
const int maxn = 200;
struct bign {
int len, s[maxn];
bign() {
memset(s, 0, sizeof(s));
len = 1;
}
bign(int num) {
*this = num;
}
bign(const char* num) {
*this = num;
}
bign operator =(int num) { //直接以整数赋值
char s[maxn];
sprintf(s, "%d", num);
*this = s;
return *this;
}
bign operator =(const char* num) { //以字符串赋值
len = strlen(num);
for(int i = 0; i < len; i++)
s[i] = num[len - i - 1] - '0';
return *this;
}
string str() const { //将bign转化成字符串
string res = "";
for(int i = 0; i < len; i++)
res = (char) (s[i] + '0') + res;
if(res == "")
res = "0";
return res;
}
bign operator +(const bign& b) const { //重载+号运算
bign c;
c.len = 0;
for(int i = 0, g = 0; g || i < max(len, b.len); i++) {
int x = g;
if(i < len) x += s[i];
if(i < b.len) x += b.s[i];
c.s[c.len++] = x % 10;
g = x / 10;
}
return c;
}
void clean() { //去掉前到0
while(len > 1 && !s[len - 1])
len--;
}
bign operator *(const bign& b) { //重载*号运算
bign c;
c.len = len + b.len;
for(int i = 0; i < len; i++)
for(int j = 0; j < b.len; j++)
c.s[i + j] += s[i] * b.s[j];
for(int i = 0; i < c.len - 1; i++) {
c.s[i + 1] += c.s[i] / 10;
c.s[i] %= 10;
}
c.clean();
return c;
}
bign operator -(const bign& b) { //重载-号运算
bign c;
c.len = 0;
for(int i = 0, g = 0; i < len; i++) {
int x = s[i] - g;
if(i < b.len)
x -= b.s[i];
if(x >= 0)
g = 0;
else {
g = 1;
x += 10;
}
c.s[c.len++] = x;
}
c.clean();
return c;
}
bool operator <(const bign& b) const { //重载<号运算
if(len != b.len)
return len < b.len;
for(int i = len - 1; i >= 0; i--)
if(s[i] != b.s[i])
return s[i] < b.s[i];
return false;
}
bool operator >(const bign& b) const { //重载>号运算
return b < *this;
}
bool operator <=(const bign& b) { //重载<=号运算
return !(b > *this);
}
bool operator ==(const bign& b) { //重载>=号运算
return !(b < *this) && !(*this < b);
}
bign operator +=(const bign& b) { //重载+=号运算
*this = *this + b;
return *this;
}
};
istream& operator >>(istream &in, bign& x) { //重载输入运算符
string s;
in >> s;
x = s.c_str();
return in;
}
ostream& operator <<(ostream &out, const bign& x) { //重载输出运算符
out << x.str();
return out;
}
bign dp[103];
int main() {
int i, j;
dp[0] = 1;
dp[1] = 1;
for(i = 2; i <= 100; i++)
for(j = 0; j < i; j++)
dp[i] += dp[j]*dp[i-j-1];
int n;
while( ~scanf("%d", &n)) {
if(n == -1)
break;
cout << dp[n] << endl;
}
return 0;
}
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