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c++

Posted by 9974 at 2013-03-09 11:42:31 on Problem 2084
#include <cstdio>
#include <cstring>
#include <iostream>
#include <string>
using namespace std;

const int maxn = 200;
struct bign {
	int len, s[maxn];

	bign() {
		memset(s, 0, sizeof(s));
		len = 1;
	}

	bign(int num) {
		*this = num;
	}

	bign(const char* num) {
		*this = num;
	}

	bign operator =(int num) { //直接以整数赋值
		char s[maxn];
		sprintf(s, "%d", num);
		*this = s;
		return *this;
	}

	bign operator =(const char* num) { //以字符串赋值
		len = strlen(num);
		for(int i = 0; i < len; i++)
			s[i] = num[len - i - 1] - '0';
		return *this;
	}

	string str() const { //将bign转化成字符串
		string res = "";
		for(int i = 0; i < len; i++)
			res = (char) (s[i] + '0') + res;
		if(res == "")
			res = "0";
		return res;
	}

	bign operator +(const bign& b) const { //重载+号运算
		bign c;
		c.len = 0;
		for(int i = 0, g = 0; g || i < max(len, b.len); i++) {
			int x = g;
			if(i < len) x += s[i];
			if(i < b.len) x += b.s[i];
			c.s[c.len++] = x % 10;
			g = x / 10;
		}
		return c;
	}

	void clean() { //去掉前到0
		while(len > 1 && !s[len - 1])
			len--;
	}

	bign operator *(const bign& b) { //重载*号运算
		bign c;
		c.len = len + b.len;
		for(int i = 0; i < len; i++)
			for(int j = 0; j < b.len; j++)
				c.s[i + j] += s[i] * b.s[j];
		for(int i = 0; i < c.len - 1; i++) {
			c.s[i + 1] += c.s[i] / 10;
			c.s[i] %= 10;
		}
		c.clean();
		return c;
	}

	bign operator -(const bign& b) { //重载-号运算
		bign c;
		c.len = 0;
		for(int i = 0, g = 0; i < len; i++) {
			int x = s[i] - g;
			if(i < b.len)
				x -= b.s[i];
			if(x >= 0)
				g = 0;
			else {
				g = 1;
				x += 10;
			}
			c.s[c.len++] = x;
		}
		c.clean();
		return c;
	}

	bool operator <(const bign& b) const { //重载<号运算
		if(len != b.len)
			return len < b.len;
		for(int i = len - 1; i >= 0; i--)
			if(s[i] != b.s[i])
				return s[i] < b.s[i];
		return false;
	}

	bool operator >(const bign& b) const { //重载>号运算
		return b < *this;
	}

	bool operator <=(const bign& b) { //重载<=号运算
		return !(b > *this);
	}

	bool operator ==(const bign& b) { //重载>=号运算
		return !(b < *this) && !(*this < b);
	}

	bign operator +=(const bign& b) { //重载+=号运算
		*this = *this + b;
		return *this;
	}
};

istream& operator >>(istream &in, bign& x) { //重载输入运算符
	string s;
	in >> s;
	x = s.c_str();
	return in;
}

ostream& operator <<(ostream &out, const bign& x) { //重载输出运算符
	out << x.str();
	return out;
}

bign dp[103];
int main() {
	int i, j;
	dp[0] = 1;
	dp[1] = 1;
	for(i = 2; i <= 100; i++)
		for(j = 0; j < i; j++)
			dp[i] += dp[j]*dp[i-j-1];
	int n;
	while( ~scanf("%d", &n)) {
		if(n == -1)
			break;
		cout << dp[n] << endl;
	}
	return 0;
}

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