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要考虑某个字母没有逆的情况,这个时候mirro是不存在的。我也在这个地方WA了好几次,后来仔细读题才发现的。In Reply To:WA 的我心都碎了。。。大侠帮帮忙 Posted by:twotwotwo at 2013-02-27 22:24:05 > #include<iostream>
> #include<string.h>
> #include<stdio.h>
> using namespace std;
> int main()
> {
> char str[100];
> string s1="AEHIJLMOSTUVWXYZ12358";
> string s2="A3HILJMO2TUVWXY51SEZ8";
> while(scanf("%s",str)!='EOF')
> {
> int len=strlen(str);
> int i,j;
> for(i=0;str[i]==str[len-i-1]&&i<len;i++);
> bool palin=false;
> bool mirror=true;
> if(i==len)
> palin=true;
> for(i=0;i<len;i++)
> {
> for(j=0;j<21;j++)
> {
> if(str[i]==s1[j])
> if(s2[j]==str[len-i-1])
> break;
> }
> if(j==21)
> {
> mirror=false;
> break;
> }
> }
> cout<<str;
> if(palin)
> {
> if(mirror)
> cout<<" -- is a mirrored palindrome."<<endl;
> else
> cout<<" -- is a regular palindrome."<<endl;
> }
> else
> {
> if(mirror)
> cout<<" -- is a mirrored string."<<endl;
> else
> cout<<" -- is not a palindrome."<<endl;
> }
> cout<<endl;
> }
> return 0;
> }
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