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pascal 题解var
n,m,l,r,mid:longint;
s:ansistring;
once:boolean;
sa,rank,key1,key2,height,belong:array [1..300000] of longint;
v:array [0..1001] of boolean;
procedure init;
var
i,j,k:longint;
s1:ansistring;
begin
n:=0; s:=''; k:=0;
readln(m); l:=1; r:=0;
if m=0 then halt;
for i:=1 to m do
begin
readln(s1); if length(s1)>r then r:=length(s1);
for j:=1 to length(s1) do begin s1[j]:=chr(ord(s1[j])+10); belong[n+j]:=i; end;
inc(k); s1:=s1+chr(k); belong[n+length(s1)]:=0;
s:=s+s1; n:=n+length(s1);
end;
for i:=1 to n do rank[i]:=ord(s[i]);
end;
procedure qsort(x,y:longint);
var
p,q,mid1,mid2,t:longint;
begin
p:=x;
q:=y;
mid1:=key1[(x+y) div 2];
mid2:=key2[(x+y) div 2];
repeat
while (key1[x]<mid1) or ((key1[x]=mid1) and (key2[x]<mid2)) do inc(x);
while (key1[y]>mid1) or ((key1[y]=mid1) and (key2[y]>mid2)) do dec(y);
if x<=y then
begin
t:=key1[x]; key1[x]:=key1[y]; key1[y]:=t;
t:=key2[x]; key2[x]:=key2[y]; key2[y]:=t;
t:=sa[x]; sa[x]:=sa[y]; sa[y]:=t;
inc(x); dec(y);
end;
until x>y;
if x<q then qsort(x,q);
if p<y then qsort(p,y);
end;
procedure suffix_array;
var
i,tot,p:longint;
begin
p:=1;
while p<n do
begin
for i:=1 to n do key1[i]:=rank[i];
for i:=1 to n do key2[i]:=rank[i+p];
for i:=1 to n do sa[i]:=i;
qsort(1,n); rank[sa[1]]:=1; tot:=1;
for i:=2 to n do
begin
if (key1[i]<>key1[i-1]) or (key2[i]<>key2[i-1]) then inc(tot);
rank[sa[i]]:=tot;
end;
if tot=n then break;
p:=p*2;
end;
for i:=1 to n do rank[sa[i]]:=i;
end;
procedure make_height;
var
i,j,h:longint;
begin
h:=0;
for i:=1 to n do
begin
if rank[i]=1 then begin height[1]:=0; continue; end;
j:=sa[rank[i]-1];
while s[i+h]=s[j+h] do inc(h);
height[rank[i]]:=h;
if h>0 then dec(h);
end;
end;
function ok(x:longint):boolean;
var
i,j,k,tot:longint;
begin
fillchar(v,sizeof(v),false);
v[0]:=true; tot:=0;
for i:=2 to n do
begin
if height[i]<x then
begin
fillchar(v,sizeof(v),false); v[0]:=true; tot:=0; continue;
end;
if v[belong[sa[i]]]=false then
begin
v[belong[sa[i]]]:=true;
inc(tot);
end;
if v[belong[sa[i-1]]]=false then
begin
v[belong[sa[i-1]]]:=true;
inc(tot);
end;
if tot>m div 2 then exit(true);
end;
exit(false);
end;
procedure print(x:longint);
var
i,j,k,tot:longint;
flag:boolean;
begin
fillchar(v,sizeof(v),false);
v[0]:=true; tot:=0; flag:=true;
for i:=2 to n do
begin
if height[i]<x then
begin
fillchar(v,sizeof(v),false); v[0]:=true; tot:=0; flag:=true; continue;
end;
if v[belong[sa[i]]]=false then
begin
v[belong[sa[i]]]:=true;
inc(tot);
end;
if v[belong[sa[i-1]]]=false then
begin
v[belong[sa[i-1]]]:=true;
inc(tot);
end;
if (tot>m div 2) and flag then
begin
for j:=sa[i-1] to sa[i-1]+x-1 do write(chr(ord(s[j])-10));
writeln;
flag:=false;
end;
end;
end;
procedure main;
var
ans:longint;
begin
ans:=0;
while l<=r do
begin
mid:=(l+r) div 2;
if ok(mid) then begin ans:=mid; l:=mid+1; end
else r:=mid-1;
end;
if ans<>0 then print(ans)
else writeln('?');
end;
begin
once:=false;
while true do
begin
init;
if once then writeln;
once:=true;
suffix_array;
make_height;
main;
end;
end.
把数组从500000变成1000就AC 原来TLE...
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