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上代码,二分法#include<stdio.h>
#include<stdlib.h>
int list[40000];
int t,n,num,res,i,w;
int binary_search(int left,int right,int path)
{ int mid;
while(left<=right)
{
mid=(left+right)/2;
if(list[mid]<path) left=mid+1;
else right=mid-1;
}
return right;//输出大于等于num的最小的数的位置
}
int main()
{
scanf("%d",&t);
while(t--)
{
scanf("%d",&n);
scanf("%d",&num);
list[0]=num;
res=1;
for(i=1;i<n;i++)
{
scanf("%d",&num);
if(num>list[res-1]) list[res++]=num;//比当前的数大的话插在后面
else
if(num<list[res-1])
{
w=binary_search(0,res-1,num);//如果小的话在前面找到合适的位置插入
list[w+1]=num;
}
}
printf("%d\n",res);
}
return 0;
}
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