#include<iostream>  
using namespace std;  
  
int main()  
{  
    int p,e,i,d;  
    int time=1;  
    while(cin>>p>>e>>i>>d)  
    {  
        if(p==-1 && e==-1 && i==-1 && d==-1)  
            break;  
  
        int lcm=21252; 
        int n=(5544*p+14421*e+1288*i-d+21252)%21252;  
        if(n==0)  
            n=21252;  
        cout<<"Case "<<time++<<": the next triple peak occurs in "<<n<<" days."<<endl;  
    }  
    return 0;  
}  

• Re:大水题,中国余数定理 (507) 201319025 2016-04-27 10:44:52