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wa的请注意!合并的代码很容易写错! #include <cstdio> #include <string.h> #include <cstdlib> #include <algorithm> using namespace std; const int NMax=550; int N,M,G[NMax][NMax],dist[NMax],map[NMax]; bool inA[NMax]; int Dinic() { //1.min=MAXINT,固定一个顶点P //2.从点P用类似prim的s算法扩展出“最大生成树”,记录最后扩展的顶点和最后扩展的边 //3.计算最后扩展到的顶点的切割值(即与此顶点相连的所有边权和),若比min小更新min //4.合并最后扩展的那条边的两个端点为一个顶点(当然他们的边也要合并,这个好理解吧?) //5.转到2,合并N-1次后结束 //6.min即为所求,输出min int ret=(~0u>>1),s=1,pre; for(int i=1;i<=N;i++) map[i]=i; while(N>1) { memset(inA,0,sizeof(inA)); inA[map[s]]=1; int lastx,lasty;pre=s; for(int i=1;i<=N;i++) dist[map[i]]=G[map[s]][map[i]]; for(int I=1;I<N;I++) { int next=-1; for(int i=2;i<=N;i++) if(!inA[map[i]]&&(next==-1||dist[map[i]]>dist[map[next]])) next=i; inA[map[next]]=1; for(int i=1;i<=N;i++) if(!inA[map[i]]) dist[map[i]]+=G[map[next]][map[i]]; if(I==N-1) {lastx=pre;lasty=next;} pre=next; } ret=min(ret,dist[map[lasty]]); for(int i=1;i<=N;i++) G[map[lastx]][map[i]]=G[map[i]][map[lastx]]=G[map[lastx]][map[i]]+G[map[i]][map[lasty]]; //就是上一行,千万不要写成G[map[lastx]][map[lasty]]+G[map[i]][map[lasty]] map[lasty]=map[N--]; } return ret==(~0u>>1)?0:ret; } int main() { while(scanf("%d%d",&N,&M)!=EOF) { int x,y,z; memset(G,0,sizeof(G)); for(int i=1;i<=M;i++) { scanf("%d%d%d",&x,&y,&z); x++;y++; G[x][y]+=z;G[y][x]+=z; } printf("%d\n",Dinic()); } return 0; } Followed by: Post your reply here: |
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