| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
int step[65535]={0} 就WA int step[65535] 就AC。。。 迷茫了 求指点
#include <iostream>
using namespace std;
int step[65535]={0}; //记录步骤
bool flag[65535]={false}; //防止重复搜索
unsigned short qState[65535]; //搜索的状态,正好可以用一个16位的无符号短整形表示
int rear = 0; //队列尾指针
int top = 0; //队列头指针
///初始化:读入棋盘初始状态并把它转化为整数存入队列头,黑的位为1白的为0
void Init()
{
unsigned short temp = 0;
char c;
for(int i=0; i < 4; i++)
for(int j = 0; j < 4; j++)
{
cin>>c;
if('b' == c)
temp |= (1<<(i*4+j));
}
qState[rear++] = temp;
flag[temp] = true;
}
///翻转一个棋子并按规则对齐周围棋子附加影响
unsigned short move(unsigned short state, int i)
{
unsigned short temp=0;
temp |= (1<<i);
if((i+1)%4 != 0) //右,且不在最右边
temp |= (1<<(i+1));
if(i%4 != 0) //左,且不在最左边
temp |= (1<<(i-1));
if(i+4 < 16) //下
temp |= (1<<(i+4));
if(i-4 >= 0) //上
temp |= (1<<(i-4));
return (state ^ temp);
}
//广度优先搜索,从队列中循环取出状态,并把翻转16次(即所有情况),一旦发现满足要求的立即停止,否则加入队列
bool BFS()
{
while(rear > top)
{
unsigned short state = qState[top++];
//qState.pop();
if(0 == state || 65535 == state)
{
cout<<step[state];
return true;
}
unsigned short temp=0;
for (int i=0;i<16;i++){
temp = move(state,i);
if(!flag[temp]){
qState[rear++] = temp;
flag[temp] = true;
step[temp] = step[state]+1;
}
}
}
return false;
}
int main(void)
{
Init();
if(!BFS()) cout<<"Impossible";
}
就是step那个数组用来记录步数的。
int step[65535]={0};就WA
int step[65535] 就AC。。。
迷茫了
Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator