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两次Floyd居然过了→ →

Posted by lsdnlgd at 2012-12-07 18:05:17 on Problem 3687 
第二次加上
if(!E[i][k] && !E[k][i])
    E[i][k] = i<k;
if(!E[j][k] && !E[k][j])
    E[k][j] = k<j;
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