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STL排序就是强大。。。。贴个弱智代码#include <iostream> #include <algorithm> using namespace std; #define NUM 120 struct node{ int x; int y; int num; }N[NUM*NUM]; int M[NUM][NUM]; int P[NUM][NUM]; bool cmp(const node & a,const node &b){ return a.num>b.num; } int main() { int ans=1; int h,w,temp; cin>>h>>w; int i,j,n; for (i=0;i<h;i++) for (j=0;j<w;j++){ cin>>n;M[i][j]=n; N[i*w+j].x=i;N[i*w+j].y=j;N[i*w+j].num=n; } sort(N,N+h*w,cmp); for (i=0;i<h*w;i++){ temp=1; if (N[i].y>0 && M[N[i].x][N[i].y-1]>N[i].num && P[N[i].x][N[i].y-1]+1>temp) temp = P[N[i].x][N[i].y-1]+1; if (N[i].y<w && M[N[i].x][N[i].y+1]>N[i].num && P[N[i].x][N[i].y+1]+1>temp) temp = P[N[i].x][N[i].y+1]+1; if (N[i].x>0 && M[N[i].x-1][N[i].y]>N[i].num && P[N[i].x-1][N[i].y]+1>temp) temp = P[N[i].x-1][N[i].y]+1; if (N[i].x<h && M[N[i].x+1][N[i].y]>N[i].num && P[N[i].x+1][N[i].y]+1>temp) temp = P[N[i].x+1][N[i].y]+1; P[N[i].x][N[i].y]=temp; if (temp>ans) ans=temp; } cout<<ans<<endl; return 0; } Followed by: Post your reply here: |
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