#include<iostream>
#include<string>
using namespace std;

char shift(char x)
{
    return (x - 'A' + 21) % 26 + 'A';   //21 = 26 - 5
}

int main()
{
    string a,b,c;
    while(cin >> a && a != "ENDOFINPUT")
    {   
        string s;
        cin.ignore(1000,'\n');
        getline(cin,s);
        for(int i = 0; i < s.length(); i++)
        {   
            if(s[i] - 'A' >= 0 && s[i] - 'A' <= 25) 
                s[i] = shift(s[i]);
        }   
        cin >> c;
        for(int i = 0; i < s.length(); i++)
            cout << s[i];
        cout << endl;
    }   
    return 0;
}

• Re:居然还有水题，其实这个位移可以稍稍借用下补码的思想，帖下~ (671) CNSpary 2014-01-01 08:27:09