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呜呜,虽然水,还是wa了好多次,现在才知道有公式#include<iostream> #include <string> using namespace std; int T,N; int main() { while(cin>>T>>N && T ) { string t_name; long long sum=0,scores; long long ans=0; for(int i=1;i<=T;++i){ cin>>t_name>>scores;sum+=scores;} for(ans=0;sum && ans<=N;++ans)if((N-ans)*3+ans*2==sum || ans*2==sum){sum=0;break;} cout<<ans<<endl; } return 0; } Followed by: Post your reply here: |
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