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一个方法搞定,很好做啊,!A的In Reply To:Re:这题矩形位置摆放判定很恶心……与其说是2-sat题,不如说是细节题…… Posted by:peargobble at 2011-03-30 15:08:48 bool cross(int xamin,int xamax,int yamin,int yamax, int xbmin,int xbmax,int ybmin,int ybmax) { if(xbmax<=xamin)return false; if(xbmin>=xamax)return false; if(ybmin>=yamax)return false; if(ybmax<=yamin)return false; return true; } Followed by: Post your reply here: |
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