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第二次做这道题,换个string来保存,自认为想法比较神奇,呵呵,虽然效率不高#include<iostream>
#include <cstring>
#include <string>
using namespace std;
bool board[27][27],is_find;
int p,q,T;
int dir[8][2]={{-2,-1},{-2,1},{-1,-2},{-1,2},{1,-2},{1,2},{2,-1},{2,1}};
string ans;
bool DFS(int i,int j,int step)
{
if(i<=0 || j<=0 || i>p || j>q || board[i][j]) return false;
board[i][j]=true;
if(step==p*q-1) return true;
for(int k=0;k<8;++k)
{
int di=i+dir[k][1];
int dj=j+dir[k][0];
if(DFS(di,dj,step+1))
{
ans.insert(0,1,di+'0');
ans.insert(0,1,dj+'A'-1);
return true;
}
}
board[i][j]=false;
return false;
}
int main()
{
cin>>T;
for(int s=1;s<=T;++s)
{
cin>>p>>q;
ans.clear();
is_find=false;
for(int i=1;i<=p && !is_find;++i)
{
for(int j=1;j<=q;++j)
{
memset(board,false,sizeof(board));
if(DFS(i,j,0)){ ans.insert(0,1,i+'0');ans.insert(0,1,j+'A'-1);is_find=true;break;}
}
}
cout<<"Scenario #"<<s<<":"<<endl;
if(ans.empty())cout<<"impossible"<<endl<<endl;
else cout<<ans<<endl<<endl;
}
return 0;
}
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