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又被坑了,代码

Posted by 529450 at 2012-10-11 22:39:27 on Problem 1248
#include<iostream>
using namespace std; 
#include<algorithm>
#include<string.h>
/*bool compare(char a,char b)
 {
      return a>b;
 }*/

int main()
{
	long target;
	char s[14],ch;
	int j,i,k,l,m,n,leap;
	 int a[14];
	while(cin>>target>>s)
	{
		l=strlen(s);
		leap=0;
		sort(s,s+l);
		//cout<<s<<" "<<endl;
        if(target==0&&l==3)
		{
			break;
		}
		for(i=0;i<l;i++)
		{
			a[i]=(int)s[i]-64;
			//cout<<a[i]<<" "<<s[i]<<" ";
		}
        for(i=l-1;i>=0;i--)
		{
			for(j=l-1;j>=0;j--)
			{
				for(k=l-1;k>=0;k--)
				{
					for(m=l-1;m>=0;m--)
					{
						for(n=l-1;n>=0;n--)
						{
							

						/*	cout<<a[i]<<endl;
								cout<<a[j]*a[j]<<endl;
									cout<<a[k]*a[k]*a[k]<<endl;
										cout<<a[m]*a[m]*a[m]*a[m]<<endl;
											cout<<a[n]*a[n]*a[n]*a[n]*a[n]<<endl;*/


                            if(i==j||i==k||i==m||i==n||j==k||j==m||j==n||k==m||k==n||m==n)continue;
							
							if(a[i]-a[j]*a[j]+a[k]*a[k]*a[k]-a[m]*a[m]*a[m]*a[m]+a[n]*a[n]*a[n]*a[n]*a[n]==target)
							{
								cout<<s[i]<<s[j]<<s[k]<<s[m]<<s[n]<<endl;
								leap=1;
								break;
							}
 

						}
						if(leap==1)break;
					}
					if(leap==1)break;
				}
				if(leap==1)break;
			}
			if(leap==1)break;
		}
		if(leap!=1)
			cout<<"no solution"<<endl;
	}
	return 0;
}

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