| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
119行手写堆维护~忘记传参时怎么传函数了只好把大根堆和小根堆的维护各写一次了QAQ结果我唯一会写的一个数据结构还写错了QAQ#include <cstdio>
#include <iostream>
using namespace std;
#define N 1000010
int pos1[N],pos2[N];
struct Heap
{
int key,opp;
}heap1[N],heap2[N];
int n,k;
int ans1[N],ans2[N];
void build_down1(int father)
{
int son=father*2;
while (son<=k)
{
if(heap1[son+1].key>heap1[son].key && son+1<=k)son++;
if(heap1[son].key>heap1[father].key)
{
swap(pos1[heap1[son].opp],pos1[heap1[father].opp]);
swap(heap1[son],heap1[father]);
}
else return;
father=son;
son=father*2;
}
}
void build_down2(int father)
{
int son=father*2;
while (son<=k)
{
if(heap2[son+1].key<heap2[son].key && son+1<=k)son++;
if(heap2[son].key<heap2[father].key)
{
swap(pos2[heap2[son].opp],pos2[heap2[father].opp]);
swap(heap2[son],heap2[father]);
}
else return;
father=son;
son=father*2;
}
}
void build_up1(int son)
{
int father=son/2;
while (father>=1)
{
if(heap1[father].key<heap1[son].key)
{
swap(pos1[heap1[father].opp],pos1[heap1[son].opp]);
swap(heap1[father],heap1[son]);
}
else break;
son=father;
father=son/2;
}
}
void build_up2(int son)
{
int father=son/2;
while (father>=1)
{
if(heap2[father].key>heap2[son].key)
{
swap(pos2[heap2[father].opp],pos2[heap2[son].opp]);
swap(heap2[father],heap2[son]);
}
else break;
son=father;
father=son/2;
}
}
int main ()
{
int i,j;
scanf("%d%d",&n,&k);
for(i=1;i<=k;i++)
{
pos1[i]=pos2[i]=heap1[i].opp=i;
scanf("%d",&heap1[i].key);
heap2[i]=heap1[i];
}
for(i=k/2;i>=1;i--)
{
build_down1(i);
build_down2(i);
}
ans1[++ans1[0]]=heap1[1].key;
ans2[++ans2[0]]=heap2[1].key;
for(i=k+1;i<=n;i++)
{
int a,b1,b2,zzz=(i%k==0?k:i%k);
scanf("%d",&a);
b1=heap1[pos1[zzz]].key;
b2=heap2[pos2[zzz]].key;
heap1[pos1[zzz]].key=heap2[pos2[zzz]].key=a;
if(a>b1)build_up1(pos1[zzz]);
else build_down1(pos1[zzz]);
if(a<b2)build_up2(pos2[zzz]);
else build_down2(pos2[zzz]);
ans1[++ans1[0]]=heap1[1].key;
ans2[++ans2[0]]=heap2[1].key;
}
for(i=1;i<=ans2[0];i++)
{
printf("%d",ans2[i]);
if(i<ans2[0])printf(" ");
else printf("\n");
}
for(i=1;i<=ans1[0];i++)
{
printf("%d",ans1[i]);
if(i<ans1[0])printf(" ");
else printf("\n");
}
return 0;
}
Followed by:
Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator