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重做有感In Reply To:有一位同学做出了此题的DP解! Posted by:yc5_yc at 2012-09-14 17:23:53 重做中……
2A
思路清晰了几倍,重做真好!
#include <cstdio>
#include <algorithm>
using namespace std;
const int NMax=2100;
int N,M,A[NMax][NMax];
int S1[NMax],S2[NMax],Heap[NMax];
int main()
{
int T;
scanf("%d",&T);
while(T--) {
scanf("%d%d",&N,&M);
for(int i=1;i<=N;i++)
for(int j=1;j<=M;j++)
scanf("%d",&A[i][j]);
for(int i=1;i<=M;i++) S1[i]=A[1][i];
sort(S1+1,S1+M+1);
for(int i=2;i<=N;i++) {
for(int j=1;j<=M;j++) Heap[j]=A[i][1]+S1[j];
make_heap(Heap+1,Heap+M+1);
for(int j=2;j<=M;j++) {
for(int k=1;k<=M;k++) if(A[i][j]+S1[k]<Heap[1]){
pop_heap(Heap+1,Heap+M+1);
Heap[M]=A[i][j]+S1[k];
push_heap(Heap+1,Heap+M+1);
}
}
for(int j=1;j<=M;j++) S1[j]=Heap[j];
sort(S1+1,S1+M+1);
}
for(int i=1;i<M;i++) printf("%d ",S1[i]);
printf("%d\n",S1[M]);
}
getchar();getchar();
return 0;
}
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