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Re:赤裸裸的普里姆怎会超时??

Posted by wadefk at 2012-09-03 17:16:23 on Problem 1258
In Reply To:赤裸裸的普里姆怎会超时?? Posted by:13091118 at 2010-08-13 17:10:26
> #include<stdio.h>
> int n,graph[100][100],dis[100],use[100];
> void prim(){
> 	int i,j,k,m,min;
> 	int sum=0;
> 	for(i=1;i<=n;i++){
> 		dis[i]=graph[1][i];
> 		use[i]=1;
> 	}
> 	use[1]=0;
> 	for(i=1;i<n;i++){
> 		min=0x7fffffff;
> 		for(k=2;k<=n;k++)
> 			if(use[k]&&dis[k]<min){
> 				min=dis[k];
> 				m=k;
> 			}
> 			sum+=min;
> 			use[m]=0;
> 			for(j=1;j<=n;j++)
> 				if(use[j]&&graph[m][j]!=0&&dis[j]>graph[m][j])
> 				
> 					dis[j]=graph[m][j];
> 			
> 		
> 	}
> 	printf("%d\n",sum);
> 	
> }
> int main(){
> 	while(scanf("%d",&n)!=EOF){
> 	
> 	int i,j;
> 	for(i=1;i<=n;i++)
> 		for(j=1;j<=n;j++)
> 			scanf("%d",&graph[i][j]);
> 		prim();
> 	}
> 		return 0;
> 
> }

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