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Re:赤裸裸的普里姆怎会超时??In Reply To:赤裸裸的普里姆怎会超时?? Posted by:13091118 at 2010-08-13 17:10:26 > #include<stdio.h>
> int n,graph[100][100],dis[100],use[100];
> void prim(){
> int i,j,k,m,min;
> int sum=0;
> for(i=1;i<=n;i++){
> dis[i]=graph[1][i];
> use[i]=1;
> }
> use[1]=0;
> for(i=1;i<n;i++){
> min=0x7fffffff;
> for(k=2;k<=n;k++)
> if(use[k]&&dis[k]<min){
> min=dis[k];
> m=k;
> }
> sum+=min;
> use[m]=0;
> for(j=1;j<=n;j++)
> if(use[j]&&graph[m][j]!=0&&dis[j]>graph[m][j])
>
> dis[j]=graph[m][j];
>
>
> }
> printf("%d\n",sum);
>
> }
> int main(){
> while(scanf("%d",&n)!=EOF){
>
> int i,j;
> for(i=1;i<=n;i++)
> for(j=1;j<=n;j++)
> scanf("%d",&graph[i][j]);
> prim();
> }
> return 0;
>
> }
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