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又一超级大水题,就和A+B一样一样的..#include<iostream>
#include<string>
#include<algorithm>
int main()
{
std::ios::sync_with_stdio(false);
for(std::string s;std::cin>>s&&s!="#";)
if(std::next_permutation(s.begin(),s.end()))
std::cout<<s<<std::endl;
else
std::cout<<"No Successor"<<std::endl;
return 0;
}
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